Math Problem Statement

A group of men (all work with equal efficiency) working together can complete a job in M hours. Instead of working together, after every 8 hours, half of the men of the group working at that point of time leave the job. Continuing this way, the job is finished in 40 hours.

What is the value of M?

Solution

Let's break down the problem step by step.

Given:

  • A group of men can complete a job in MM hours if they work together continuously.
  • Instead of working continuously, after every 8 hours, half of the men leave.
  • The job is completed in 40 hours.

Step 1: Understanding the problem

Let's assume the total number of men is NN.

  • Initial phase (first 8 hours): All NN men are working.
  • Second phase (next 8 hours): Half of the men leave, so N2\frac{N}{2} men are working.
  • Third phase (next 8 hours): Half of the remaining men leave, so N4\frac{N}{4} men are working.
  • Fourth phase (next 8 hours): Half of the remaining men leave, so N8\frac{N}{8} men are working.
  • Fifth phase (final 8 hours): Half of the remaining men leave, so N16\frac{N}{16} men are working.

Step 2: Calculate the work done in each phase

Since all men work with equal efficiency, the work done is proportional to the number of men and the time they work.

  • Work done in the first 8 hours: W1=N×8W_1 = N \times 8
  • Work done in the second 8 hours: W2=N2×8=8N2=4NW_2 = \frac{N}{2} \times 8 = \frac{8N}{2} = 4N
  • Work done in the third 8 hours: W3=N4×8=8N4=2NW_3 = \frac{N}{4} \times 8 = \frac{8N}{4} = 2N
  • Work done in the fourth 8 hours: W4=N8×8=8N8=NW_4 = \frac{N}{8} \times 8 = \frac{8N}{8} = N
  • Work done in the fifth 8 hours: W5=N16×8=8N16=N2W_5 = \frac{N}{16} \times 8 = \frac{8N}{16} = \frac{N}{2}

Step 3: Total work done

The total work WW done to complete the job is the sum of the work done in each phase: W=W1+W2+W3+W4+W5W = W_1 + W_2 + W_3 + W_4 + W_5 W=8N+4N+2N+N+N2=15.5NW = 8N + 4N + 2N + N + \frac{N}{2} = 15.5N

Step 4: Relating to MM

If all NN men work together for MM hours, the work done is W=N×MW = N \times M.

Since the total work WW done is the same in both scenarios: N×M=15.5NN \times M = 15.5N M=15.5M = 15.5

Final Answer:

The value of MM is 15.5 hours.

Would you like more details on any part of this solution?


Relative questions:

  1. What happens if the men leave after every 10 hours instead of 8 hours?
  2. How would the value of MM change if a quarter of the men left after every 8 hours?
  3. What if instead of half leaving, 75% of the men left after every 8 hours?
  4. How would the calculation change if the efficiency of the men decreased by 10% every 8 hours?
  5. What is the effect on MM if the total job took 50 hours instead of 40?

Tip: When faced with a problem involving work or efficiency, it's helpful to break down the process step by step to see how each component contributes to the total outcome.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Work and Time
Geometric Progression

Formulas

Work done = Number of men × Time
Sum of a geometric series: S = a(1-r^n)/(1-r)

Theorems

-

Suitable Grade Level

Grades 10-12