Math Problem Statement

Travelling a distance of 105 km in 6 hours 5 min, a car takes 4 halts and travels with 5 different speeds Sl , S2, S3, S4, S5 (all in km/hr) for one hour each. S5 is 15 more than square of Sl , S3 is half of S5, S4 is twice the sum of Sl and S2, and S2 is half of S3. It takes total 5 hours to travel the same distance without any halt. How many hours will it take to travel with S5 without any halt? A. 4 hours B. 105/30 C. 105/40 D. 105/35

Solution

Given the problem, we need to determine how many hours it will take to travel a distance of 105 km without any halt using speed S5S_5.

Step 1: Define the speeds

Let's denote the speeds as follows:

  • S1=xS_1 = x
  • S2S_2
  • S3S_3
  • S4S_4
  • S5=x2+15S_5 = x^2 + 15

The relationships between the speeds are:

  1. S5=x2+15S_5 = x^2 + 15
  2. S3=S52=x2+152S_3 = \frac{S_5}{2} = \frac{x^2 + 15}{2}
  3. S2=S32=x2+154S_2 = \frac{S_3}{2} = \frac{x^2 + 15}{4}
  4. S4=2(S1+S2)=2(x+x2+154)S_4 = 2(S_1 + S_2) = 2\left(x + \frac{x^2 + 15}{4}\right)

Step 2: Calculate the total distance covered

The car travels at 5 different speeds for one hour each, and takes 4 halts. Therefore, the total time traveling at these speeds is 5 hours. The total distance is 105 km.

The distance covered with each speed is: Total Distance=S1+S2+S3+S4+S5=105 km\text{Total Distance} = S_1 + S_2 + S_3 + S_4 + S_5 = 105 \text{ km}

So: x+x2+154+x2+152+2(x+x2+154)+(x2+15)=105x + \frac{x^2 + 15}{4} + \frac{x^2 + 15}{2} + 2\left(x + \frac{x^2 + 15}{4}\right) + (x^2 + 15) = 105

Step 3: Simplify the equation

Let's simplify each term: x+x2+154+x2+152+2(x+x2+154)+x2+15=105x + \frac{x^2 + 15}{4} + \frac{x^2 + 15}{2} + 2\left(x + \frac{x^2 + 15}{4}\right) + x^2 + 15 = 105

Simplify the terms within the equation:

  • Combine x2+154+2(x+x2+154)\frac{x^2 + 15}{4} + 2\left(x + \frac{x^2 + 15}{4}\right) into one expression.
  • Combine all the x's and the x2x^2 terms.

But, let's directly calculate time for S5S_5 as the problem asks for it:

  • Since S5=x2+15S_5 = x^2 + 15 and the total distance is 105 km.

Step 4: Calculate time taken at speed S5S_5

The time taken to travel 105 km at speed S5S_5 is: Time=DistanceSpeed=105S5=105x2+15\text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{105}{S_5} = \frac{105}{x^2 + 15}

Step 5: Solve for time using choices

Substitute each option and see if it satisfies the original equation.

  • Option A: 4 hours 4=105x2+15x2+15=1054=26.25x2=11.254 = \frac{105}{x^2 + 15} \Rightarrow x^2 + 15 = \frac{105}{4} = 26.25 \Rightarrow x^2 = 11.25

  • Option B: 105/30 hours 10530=105x2+15x2+15=30x2=15\frac{105}{30} = \frac{105}{x^2 + 15} \Rightarrow x^2 + 15 = 30 \Rightarrow x^2 = 15

  • Option C: 105/40 hours 10540=105x2+15x2+15=40x2=25\frac{105}{40} = \frac{105}{x^2 + 15} \Rightarrow x^2 + 15 = 40 \Rightarrow x^2 = 25

  • Option D: 105/35 hours 10535=105x2+15x2+15=35x2=20\frac{105}{35} = \frac{105}{x^2 + 15} \Rightarrow x^2 + 15 = 35 \Rightarrow x^2 = 20

Comparing the simplest time to match options: x2=25x^2 = 25, x=5x = 5.

Correct answer: 105/40105/40 (Option C)

So, the time taken to travel the distance without any halt at speed S5S_5 is 105/40\boxed{105/40} or 2.625 hours.


Do you want details or have any questions? Here are some related questions:

  1. How does time vary with speed when traveling the same distance?
  2. How can we simplify the calculation process in problems involving multiple variables?
  3. What is the relationship between distance, speed, and time?
  4. What other types of problems can be solved with the concept of speed and time?
  5. How do real-world constraints, like halts and speed changes, affect travel time?

Tip: Breaking down complex equations into simpler parts can make problem-solving easier and more efficient.

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Math Problem Analysis

Mathematical Concepts

Speed, Distance, Time Relationships
Quadratic Equations

Formulas

Time = Distance / Speed

Theorems

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Suitable Grade Level

Grades 9-12