The problem provided is about calculating the total supplied voltage $E_T$ in a series circuit, given the resistances $R_1$, $R_2$, and the current $I_1$.

Given:

• $R_1 = 13.4 \, \Omega$
• $R_2 = 15.8 \, \Omega$
• $I_1 = 14.3 \, \text{A}$

Series Circuit Formula:

In a series circuit, the total resistance $R_T$ is the sum of the individual resistances: $R_T = R_1 + R_2$ $R_T = 13.4 \, \Omega + 15.8 \, \Omega = 29.2 \, \Omega$

The total supplied voltage $E_T$ is then calculated using Ohm's Law: $E_T = I_1 \times R_T$ Substitute the values: $E_T = 14.3 \, \text{A} \times 29.2 \, \Omega = 417.56 \, \text{V}$

Rounding to one decimal place, the total supplied voltage is: $E_T \approx 417.6 \, \text{V}$

Final Answer:

$\boxed{417.6 \, \text{V}}$

Would you like more details or further clarification on any step?

Related Questions:

1. How would the total voltage change if one resistor value increased?
2. What happens if the resistors were connected in parallel instead of in series?
3. How do you calculate the total power consumed by the circuit?
4. What if the current value was doubled—how would that impact the voltage?
5. Can you explain the relationship between voltage, current, and resistance?

Tip:

Always remember in a series circuit, the same current flows through all resistors, but the total resistance is the sum of all individual resistances.