From the image, the question reads:

"Two resistors are connected in parallel with a battery of 17V. The first resistor has a resistance of 13.6 Ω, and the second resistor has a resistance of 28.3 Ω. There is a switch in the circuit.
What is the total resistance in the circuit?
Record your answer to 2 decimal places."

To calculate the total resistance for resistors in parallel, use the formula:

$\frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2}$

Where:

• $R_1 = 13.6 \, \Omega$
• $R_2 = 28.3 \, \Omega$

Let me calculate that. Given resistances in ohms R1 = 13.6 R2 = 28.3

Total resistance calculation for parallel resistors

R_total = 1 / ((1 / R1) + (1 / R2)) round(R_total, 2)The total resistance in the circuit is 9.19 Ω.

Would you like me to explain the steps in more detail or assist further with related questions?

Here are 5 related questions to expand your understanding:

1. How does the voltage remain the same across resistors in parallel?
2. What happens to the total resistance if a third resistor is added in parallel?
3. Can the total resistance in a parallel circuit ever be greater than the smallest resistor?
4. How is the current distributed in a parallel circuit?
5. How does a switch affect the behavior of a circuit with resistors in parallel?

Tip: When resistors are connected in parallel, the total resistance is always less than the smallest individual resistor.