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The problem describes two posters with a length of \( x \) inches. The first poster has a width of \( x + 7 \) inches, and the second poster has a width of \( x + 2 \) inches. To find the total area of wall these posters will cover, we need to calculate the area of each poster and then sum the areas.

### Area of the first poster:
- Length = \( x \)
- Width = \( x + 7 \)
- Area = \( x(x + 7) = x^2 + 7x \)

### Area of the second poster:
- Length = \( x \)
- Width = \( x + 2 \)
- Area = \( x(x + 2) = x^2 + 2x \)

### Total area covered by both posters:
We add the two areas together:
\[
(x^2 + 7x) + (x^2 + 2x) = 2x^2 + 9x
\]

Thus, the expression that represents the total area of the wall that the posters will cover is:
\[
2x^2 + 9x
\]

Would you like a detailed explanation of any steps, or do you have any further questions?

### Related questions:
1. How do you find the area of a rectangle using its length and width?
2. What happens if the dimensions of one of the posters change?
3. Can this formula be used for non-rectangular posters?
4. How does combining like terms work when simplifying algebraic expressions?
5. How would this change if the width of the wall itself was provided?

**Tip:** Always remember to combine like terms when simplifying algebraic expressions to get the cleanest possible form of the equation.

Augustina has 2 posters with length x inches. One poster has a width of x + 7 inches, and the other has a width of x + 2 inches. Write an expression to represent the area of wall that the posters will cover.

Find the total area of two posters with given lengths and widths using algebra. This problem demonstrates how to calculate the area of rectangles and simplify expressions. Suitable for students in Grades 7-9.

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