During a 12 hour period the temperature in a city dropped from a high of 65 degrees F to a low of -26 degrees F. What was the range of the temperatures during this period

To find the range of temperatures during the 12-hour period, we need to calculate the difference between the highest and lowest temperatures recorded during that period.

Given:
- Highest temperature: 65°F
- Lowest temperature: -26°F

The formula to find the range is:

\[ \text{Range} = \text{Highest Temperature} - \text{Lowest Temperature} \]

Substitute the given temperatures into the formula:

\[ \text{Range} = 65 - (-26) \]

Since subtracting a negative number is equivalent to adding the absolute value of that number:

\[ \text{Range} = 65 + 26 = 91 \]

Therefore, the range of temperatures during the 12-hour period is 91°F.

Would you like more details or have any questions about this calculation? Here are some related questions that might be useful for further exploration:

1. What is the average temperature during the 12-hour period?
2. How would you calculate the temperature change per hour on average?
3. What is the significance of understanding temperature ranges in meteorology?
4. How can extreme temperature ranges affect daily life and activities?
5. What are some methods to protect against drastic temperature drops?
6. How do you convert temperatures from Fahrenheit to Celsius?
7. What are some historical examples of extreme temperature changes in a short period?
8. How do weather forecasting models predict temperature changes?

**Tip:** When working with temperature ranges, always remember to account for both positive and negative values, especially when dealing with Fahrenheit and Celsius scales.

Discover how to calculate the temperature range from a high of 65°F to a low of -26°F within a 12-hour period. This problem involves basic arithmetic and temperature conversion concepts. Suitable for students in Grades 5-7.

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