Math Problem Statement

Calculate the value of the tangent of angle \(\theta\) in the given triangle diagram.

Solution

The diagram shows two right-angled triangles within one another, where we have one large triangle ABC\triangle ABC and a smaller triangle inside it. The dimensions and angles given are as follows:

  • AB=7AB = 7, AC=3AC = 3, and the hypotenuse BCBC is the longest side.
  • The smaller right triangle has one side labeled 55, and the angle at BB (marked as θ\theta) is shared by both triangles.

The problem is asking to "Calculate the value of the tangent of angle θ\theta" (which likely refers to tan(θ)\tan(\theta)).

To solve for tan(θ)\tan(\theta), we can use the trigonometric identity: tan(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} where θ\theta is in the smaller right triangle. Based on the information:

  • In the small triangle, the opposite side to θ\theta is 3, and the adjacent side (likely corresponding to ABAB) is 5.
  • Thus, we calculate: tan(θ)=35\tan(\theta) = \frac{3}{5}

Would you like a detailed step-by-step breakdown of how this is derived, or do you have any other questions?

Here are 5 related questions:

  1. What is the sine of angle θ\theta in this triangle?
  2. How would you find the length of BCBC using the Pythagorean theorem?
  3. Can you compute the cosine of angle θ\theta?
  4. How does knowing tan(θ)\tan(\theta) help in determining the slope of a line?
  5. If the triangle were scaled, how would tan(θ)\tan(\theta) change?

Tip: In right-angled triangles, the tangent of an angle is often used in slope calculations and in problems involving inclines.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Right-Angle Triangles

Formulas

\( \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \)

Theorems

Pythagorean Theorem
Trigonometric Ratios

Suitable Grade Level

Grades 8-10