Math Problem Statement

A man owns stock valued at $3000. One day the stock drops by 8%, and then gains the same percentage back the next day. How much money is the stock valued at the end of the second day?

Solution

Let's break this problem into steps:

  1. Initial value of the stock: $3000

  2. Drop by 8%: On the first day, the stock drops by 8%.

    • This means the stock loses 8% of $3000:
      0.08×3000=2400.08 \times 3000 = 240
    • The new value after the drop is: 3000240=27603000 - 240 = 2760
  3. Gain of 8%: On the second day, the stock gains 8% of the new value ($2760).

    • This means it gains 8% of $2760: 0.08×2760=220.800.08 \times 2760 = 220.80
    • The value after the gain is: 2760+220.80=2980.802760 + 220.80 = 2980.80

Thus, at the end of the second day, the stock is valued at $2980.80.


Would you like a more detailed explanation, or do you have any other questions?

Here are some related questions:

  1. How do percentage increases and decreases affect the value of an investment over time?
  2. What would happen if the stock dropped by 10% instead of 8%?
  3. How do compounded gains differ from simple percentage gains?
  4. How would this problem change if the gain on the second day were higher, say 10%?
  5. How can this principle be applied to interest calculations in finance?

Tip: Always apply percentage increases or decreases to the new amount after the change rather than the original amount to get accurate results!

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Math Problem Analysis

Mathematical Concepts

Percentage Decrease
Percentage Increase
Basic Arithmetic
Financial Mathematics

Formulas

Percentage Change Formula: Value after change = Original Value * (1 + Percentage Change)

Theorems

Percentage Change Theorem

Suitable Grade Level

Grades 6-8