
A car averages 22 mpg with a standard deviation of 3. What is the standard error if 22 of these cars were sampled for their mean average mpg?


To calculate the standard error (SE) of the mean, use the formula:

\[
SE = \frac{\sigma}{\sqrt{n}}
\]

Where:
- \(\sigma\) is the standard deviation (3 mpg),
- \(n\) is the sample size (22 cars).

Now let's compute it:

\[
SE = \frac{3}{\sqrt{22}} \approx \frac{3}{4.690} \approx 0.64
\]

So, the standard error is approximately **0.64 mpg**.

Would you like further details or have any questions?

Here are 5 related questions:
1. How is the standard error affected if the sample size increases?
2. What does the standard error represent in this context?
3. How can we decrease the standard error?
4. What is the relationship between standard deviation and standard error?
5. How would the standard error change if the standard deviation were different?

**Tip:** Increasing your sample size decreases the standard error, leading to more precise estimates of the population mean.

A car averages 22 mpg with a standard deviation of 3. What is the standard error if 22 of these cars were sampled for their mean average mpg?

Learn how to calculate the standard error for a sample of 22 cars with an average of 22 mpg and a standard deviation of 3. This problem covers statistical concepts like standard deviation, sample size, and the standard error formula. Ideal for college-level statistics students.

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