Math Problem Statement

At the start of year n, the population of a spider species is P_n. At the start of the following year, the population of the spider species is given by P_{n+1} = k * P_n, where k is a positive constant. The population of the spider species at the start of year 1 is 5 million, and the population at the start of year 2 is 6 million. (a) Work out the population of the spider species at the start of year 3. (b) Is Lewis correct in thinking that the population would continue to increase year on year after k is reduced by 0.1 at the start of year 5?

Solution

To tackle this problem, let’s break down each part step-by-step.

Problem Information

  • The population of a spider species at the start of year nn is denoted by PnP_n.
  • The population at the start of the following year is given by the recursive formula: Pn+1=kPnP_{n+1} = k \cdot P_n where kk is a positive constant.
  • We know:
    • P1=5P_1 = 5 million (start of year 1)
    • P2=6P_2 = 6 million (start of year 2)

Part (a): Calculate the Population at the Start of Year 3

  1. Find the Value of kk: From the recursive formula: P2=kP1P_2 = k \cdot P_1 Substituting the known values: 6=k56 = k \cdot 5 Solving for kk: k=65=1.2k = \frac{6}{5} = 1.2

  2. Calculate P3P_3: Now that we know k=1.2k = 1.2, we can find P3P_3 using the formula: [ P_3 = k \cdot P_2 = 1.2 \cdot 6 = 7.

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Math Problem Analysis

Mathematical Concepts

Sequences
Exponential Growth
Recursive Formulas

Formulas

P_{n+1} = k * P_n

Theorems

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Suitable Grade Level

Grades 10-12