A 2 kg ball has a kinetic energy of 20 J. What is its speed?
*

To find the speed of the ball, we can use the formula for kinetic energy:

\[
KE = \frac{1}{2}mv^2
\]

Where:
- \( KE \) is the kinetic energy,
- \( m \) is the mass,
- \( v \) is the speed.

Given:
- \( KE = 20 \) J (joules),
- \( m = 2 \) kg.

Plugging the values into the equation:

\[
20 = \frac{1}{2} \times 2 \times v^2
\]

Simplifying the equation:

\[
20 = 1 \times v^2
\]

\[
v^2 = 20
\]

Taking the square root of both sides to solve for \( v \):

\[
v = \sqrt{20}
\]

\[
v \approx 4.47 \, \text{m/s}
\]

So, the speed of the ball is approximately **4.47 m/s**.

Would you like more details on this calculation or have any questions?

Here are 5 related questions you might be interested in:
1. How does the kinetic energy change if the mass of the ball is doubled?
2. What happens to the speed if the kinetic energy is quadrupled?
3. How is kinetic energy related to momentum?
4. How would the speed change if the ball's mass was halved?
5. What is the potential energy if the ball is at a height of 5 meters?

**Tip:** Remember, kinetic energy is directly proportional to the square of the speed, so even a small increase in speed results in a larger increase in kinetic energy.

A 2 kg ball has a kinetic energy of 20 J. What is its speed?

Find out how to calculate the speed of a 2 kg ball with a kinetic energy of 20 J using the kinetic energy formula KE = (1/2)mv^2. Detailed step-by-step solution, perfect for students in Grades 8-10.

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