To determine $\sec \theta$ in the given right triangle, we use the definition of secant:

$\sec \theta = \frac{\text{Hypotenuse}}{\text{Adjacent side}}$

From the triangle:

• Hypotenuse = 10
• Adjacent side (next to angle $\theta$) = 6

Thus: $\sec \theta = \frac{10}{6} = \frac{5}{3}$

Final Answer:

$\sec \theta = \frac{5}{3}$

Would you like a detailed explanation or help solving similar problems?

Here are 5 related questions:

1. What is $\cos \theta$ in this triangle?
2. How would you calculate $\tan \theta$?
3. What is the value of $\sin \theta$?
4. How do you find the cotangent of $\theta$ in this triangle?
5. How does secant relate to cosine?

Tip: Remember, $\sec \theta = \frac{1}{\cos \theta}$. Knowing one trigonometric function helps determine others easily.