Thank you for providing the width. Let's calculate the scaled dimensions of the rectangle now that we have both the length and width.

### Given Information:
- Original length of the rectangle: 12 inches
- Original width of the rectangle: 8 inches
- Scale factor: \( \frac{2}{3} \)

### Calculating the Scaled Dimensions:

1. **Scaled Length:**
   \[
   \text{Scaled Length} = \text{Original Length} \times \text{Scale Factor}
   \]
   \[
   \text{Scaled Length} = 12 \times \frac{2}{3} = 8 \text{ inches}
   \]

2. **Scaled Width:**
   \[
   \text{Scaled Width} = \text{Original Width} \times \text{Scale Factor}
   \]
   \[
   \text{Scaled Width} = 8 \times \frac{2}{3} = \frac{16}{3} \approx 5.\overline{3} \text{ inches}
   \]

### Final Dimensions of the Scale Drawing:
- **Length:** 8 inches
- **Width:** \( \frac{16}{3} \) inches, or approximately 5.33 inches.

The dimensions of the scale drawing of the rectangle are 8 inches by 5.33 inches.

Would you like more details on any step or have any questions? Here are some related questions:

1. What is the area of the scaled rectangle?
2. How does the perimeter of the scaled rectangle compare to the original?
3. If the scale factor were \( \frac{1}{2} \), what would the new dimensions be?
4. What is the scale factor if the scaled width needs to be exactly 4 inches?
5. How do you calculate the dimensions of a rectangle if only the diagonal and scale factor are known?

**Tip:** To maintain the proportions of a scaled drawing, ensure all measurements are multiplied by the same scale factor.

Learn how to calculate the scaled dimensions of a rectangle when the original width is 8 inches. This problem involves proportional reasoning and the application of scale factor formulas in geometry. Suitable for students in Grades 6-8.

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