Math Problem Statement

show me how to calculate a rotation matrix of a coordinate system between the given start matrix A and the given desired matrix B

Solution

To calculate a rotation matrix between two coordinate systems, defined by a start matrix A and a desired matrix B, the steps below outline the process:

Steps for Calculating the Rotation Matrix:

  1. Define the Matrices: Let AA and BB represent the initial and desired coordinate systems, respectively. Each matrix should be a 3x3 matrix where each column vector represents the basis vectors of the respective coordinate system.

    \mathbf{a}_1 & \mathbf{a}_2 & \mathbf{a}_3 \end{bmatrix}, \quad B = \begin{bmatrix} \mathbf{b}_1 & \mathbf{b}_2 & \mathbf{b}_3 \end{bmatrix}$$ where $$\mathbf{a}_1, \mathbf{a}_2, \mathbf{a}_3$$ are the basis vectors of the start matrix $$A$$, and $$\mathbf{b}_1, \mathbf{b}_2, \mathbf{b}_3$$ are the basis vectors of the desired matrix $$B$$.
  2. Rotation Matrix Concept: The rotation matrix RR that transforms the coordinate system from AA to BB is given by: R=BA1R = B A^{-1} where A1A^{-1} is the inverse of the matrix AA.

    The idea is that multiplying by A1A^{-1} undoes the rotation in the original system, and multiplying by BB applies the new desired rotation.

  3. Calculate the Inverse of AA: To find A1A^{-1}, the inverse of the start matrix, use standard matrix inversion techniques:

    • If AA is orthogonal (i.e., its column vectors are orthonormal), A1=AA^{-1} = A^\top, the transpose of AA.
    • Otherwise, compute the inverse of AA using Gaussian elimination, adjugate/cofactor method, or direct matrix inversion formulas.
  4. Multiply the Matrices: Once you have A1A^{-1}, multiply it by the matrix BB: R=BA1R = B A^{-1} Perform standard matrix multiplication to get the rotation matrix RR.

  5. Interpret the Result: The resulting matrix RR is the rotation matrix that transforms the coordinate system from AA to BB. This matrix can be used to rotate vectors from the start system into the desired system.

Example:

If AA and BB are defined as follows:

1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}, \quad B = \begin{bmatrix} 0 & 1 & 0 \\ -1 & 0 & 0 \\ 0 & 0 & 1 \end{bmatrix}$$ Here, $$A$$ is the identity matrix (standard basis), and $$B$$ represents a 90° counterclockwise rotation about the z-axis. 1. The inverse of $$A$$ is: \[ A^{-1} = A = \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Matrix Operations
Rotation Matrices

Formulas

R = B A^{-1}
Inverse of matrix A: A^{-1}
If A is orthogonal, A^{-1} = A^T

Theorems

Matrix Inversion
Orthogonality

Suitable Grade Level

Undergraduate Level