I see you've uploaded an image that contains a circuit problem and a series of questions related to circuits. Let's break this down and analyze it.

For the image:

It contains three main questions:

1. Comparing two circuits (Circuit 1 and Circuit 2) with details about charge and time. You are asked to find out where the current is greater.
2. A circuit with a cell and a bulb, asking how the current changes when the charge passing through a point is doubled.
3. A complex circuit with multiple resistors (R1 to R10) where you need to tabulate the values of resistance, voltage, and current, and calculate the total resistance, total voltage, total current, and total power.

Let's analyze these questions step by step.

Question 1:

Two circuits comparison (Circuit 1 and Circuit 2):

• Circuit 1: 16 coulombs of charge flows in 16 seconds.
• Circuit 2: 12 coulombs of charge flows in 5 seconds.

We need to calculate the current in each circuit using the formula: $I = \frac{Q}{t}$ where $I$ is current, $Q$ is the charge, and $t$ is time.

For Circuit 1: $I_1 = \frac{16}{16} = 1 \, \text{A}$

For Circuit 2: $I_2 = \frac{12}{5} = 2.4 \, \text{A}$

Answer: The current in Circuit 2 is greater.

Question 2:

If the charge flowing through a point doubles, the current doubles because current is directly proportional to charge. If the charge doubles in the same amount of time, the current will also double.

If the initial current is: $I = \frac{Q}{t}$ When charge $Q$ is doubled, the new current is: $I_{\text{new}} = \frac{2Q}{t} = 2I$ So, the current will double.

Question 3:

Complex Circuit with Multiple Resistors (R1 to R10):

You are asked to tabulate the resistance, voltage, and current for each part of the circuit and calculate the total resistance, total voltage, and current. Without values for resistances or voltage, we can outline the process:

1. Total Resistance Calculation:

• R2 and R3 are in parallel, so their combined resistance $R_{23}$ is: $\frac{1}{R_{23}} = \frac{1}{R_2} + \frac{1}{R_3}$
• R4 and R5 are in series with $R_{23}$. $R_{235} = R_{23} + R_4 + R_5$
• R6, R7, and the parallel combination of R8 and R9 follow similar rules. $\frac{1}{R_{89}} = \frac{1}{R_8} + \frac{1}{R_9}$ Then, combine this with $R_7$, and so on. Finally, add the resistances to find the total resistance of the network.

2. Current and Voltage:

Once you find the total resistance $R_{\text{total}}$, use Ohm’s law to find the total current if the total voltage $V$ is known: $I_{\text{total}} = \frac{V}{R_{\text{total}}}$ Then, you can calculate the voltage drop across each resistor using: $V = IR$ and similarly, the current through each series and parallel section.

Would you like me to continue with further detailed steps and calculations? Let me know if you have any questions.

5 Relative Questions:

1. How would the current change if one of the resistances in a parallel branch is removed?
2. How do you calculate the power dissipated by each resistor in this circuit?
3. What happens to the total resistance if you add another resistor in series?
4. How do you find the equivalent resistance of a complex circuit?
5. How do voltage and current distribute in parallel and series combinations?

Tip:

Always simplify the circuit step by step, reducing complex parallel and series resistor networks before calculating overall quantities like total resistance and current.