The maximum number of volts, E, that can be placed across a resistor is given by E=PR, where P is the power in watts and R is the resistance in ohms. If a 2 watt resistor can have at most 40 volts of electricity across it, find the number of ohms of resistance of this resistor.

To find the resistance \( R \) of the resistor, we can use the formula provided:

\[
E = P \cdot R
\]

Here:
- \( E = 40 \) volts (maximum voltage)
- \( P = 2 \) watts (power)

Rearrange the formula to solve for \( R \):

\[
R = \frac{E}{P}
\]

Substitute the known values:

\[
R = \frac{40}{2} = 20 \ \text{ohms}
\]

So, the resistance \( R \) of the resistor is **20 ohms**.

Would you like further details or have any questions?

Here are related questions to consider:
1. How would the resistance change if the power of the resistor increased?
2. What would happen to the voltage if the resistance were doubled?
3. Can this formula be used for both AC and DC circuits?
4. What would be the power of a resistor if the voltage and resistance are known?
5. How does this relationship between power, voltage, and resistance apply to real circuits?

**Tip:** Remember that power \( P = \frac{E^2}{R} \) can be a useful variation of Ohm's law when working with voltage and resistance directly.

The maximum number of volts, E, that can be placed across a resistor is given by E = PR, where P is the power in watts and R is the resistance in ohms. If a 2 watt resistor can have at most 40 volts of electricity across it, find the number of ohms of resistance of this resistor.

Learn how to calculate the resistance of a resistor given the maximum voltage and power. This example uses Ohm's Law and explores the relationship between voltage, power, and resistance in circuits. Ideal for high school students in Grades 9-11.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation