Math Problem Statement

Sr-90 is present in 1950 with an initial activity of 10 mbq how much will remain approximately in year 2010

Solution

To determine how much of Strontium-90 (Sr-90) will remain by 2010, we need to use the concept of radioactive decay. Strontium-90 has a half-life of approximately 28.8 years.

The formula for radioactive decay is:

A(t)=A0×(12)tT1/2A(t) = A_0 \times \left( \frac{1}{2} \right)^{\frac{t}{T_{1/2}}}

Where:

  • A(t)A(t) is the activity at time tt,
  • A0A_0 is the initial activity (10 MBq in 1950),
  • T1/2T_{1/2} is the half-life (28.8 years for Sr-90),
  • tt is the time elapsed (2010 - 1950 = 60 years).

Now let's calculate the remaining activity.The remaining activity of Sr-90 in the year 2010 would be approximately 2.36 MBq, starting from 10 MBq in 1950.

Do you need more details or have any questions? Here are 5 related questions you might find interesting:

  1. How is the half-life of a radioactive substance determined experimentally?
  2. What factors influence the rate of radioactive decay?
  3. How does the decay of Sr-90 affect the environment and human health?
  4. Can the decay of a radioactive isotope like Sr-90 be reversed or slowed down?
  5. What are some common uses of Sr-90 in industry and medicine?

Tip: Understanding half-life helps estimate how long it takes for radioactive materials to decay to safe levels.

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Math Problem Analysis

Mathematical Concepts

Radioactive Decay
Exponential Decay
Half-Life

Formulas

A(t) = A_0 × (1/2)^(t / T_1/2)

Theorems

Radioactive Decay Law

Suitable Grade Level

Grades 10-12