Math Problem Statement

answer part a is 5/22 what is part b?

Answer part a is 5/22. What is part b?

Solution

To find the answer for part (b), which asks for the relative frequency of scores between 83 and 98, let's examine the histogram data provided in the image.

  1. Identify frequencies for the intervals 83–90 and 91–98:

    • For the interval 83–90, the frequency is 7.
    • For the interval 91–98, the frequency is 3.
  2. Calculate the total frequency of scores between 83 and 98: 7+3=107 + 3 = 10

  3. Determine the total frequency of all intervals: By adding up the frequencies for each interval:

    • 67–74: 5
    • 75–82: 4
    • 83–90: 7
    • 91–98: 3
    • 99–106: 3

    Total frequency: 5+4+7+3+3=225 + 4 + 7 + 3 + 3 = 22

  4. Calculate the relative frequency for scores between 83 and 98: The relative frequency is the frequency of scores from 83 to 98 divided by the total frequency: 1022=511\frac{10}{22} = \frac{5}{11}

Therefore, the relative frequency for scores between 83 and 98 is 511\frac{5}{11}.

Would you like further explanation or have any questions?

Related Questions

  1. How do you interpret relative frequency in this context?
  2. What is the relative frequency for scores in the 75–82 interval?
  3. How would you calculate the cumulative frequency up to the interval 83–90?
  4. What is the percentage representation of scores from 67–74?
  5. How would the answer change if there was a different total frequency?

Tip

Relative frequency gives insight into the proportion of occurrences in each category compared to the total, making it useful for understanding data distributions.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Relative Frequency
Data Interpretation
Statistics

Formulas

Relative frequency = (Frequency of interval) / (Total frequency)

Theorems

-

Suitable Grade Level

Grades 6-8