Math Problem Statement

Calculate the probability of the following using only the z-table (Express your answers in percentage with 2 decimal places. Ex: 4.00%)

P (z ≥ 2.1) =

Solution

To calculate the probability P(z2.1)P(z \geq 2.1) using the z-table, follow these steps:

  1. Find the z-score on the z-table:

    • The z-table provides the area to the left of the z-score. First, find the value corresponding to z=2.1z = 2.1 in the z-table.
    • The z-table value for z=2.1z = 2.1 is approximately 0.98210.9821.
  2. Convert this to the area to the right:

    • Since the z-table gives the area to the left, and we need P(z2.1)P(z \geq 2.1), which is the area to the right, subtract the table value from 1.
    • P(z2.1)=10.9821=0.0179P(z \geq 2.1) = 1 - 0.9821 = 0.0179.
  3. Convert the decimal to a percentage:

    • 0.0179×100%=1.79%0.0179 \times 100\% = 1.79\%.

Thus, the probability P(z2.1)P(z \geq 2.1) is 1.79%.

Would you like more details or have any questions?


Relative Questions:

  1. How would you calculate P(z2.1)P(z \leq 2.1) using the z-table?
  2. What is the probability P(2.1z2.1)P(-2.1 \leq z \leq 2.1)?
  3. How would you calculate P(z2.1)P(z \geq -2.1)?
  4. What is the probability P(z1.5)P(z \geq 1.5)?
  5. How do you interpret a very small probability like P(z2.1)P(z \geq 2.1) in a real-world scenario?
  6. What does the z-score of 2.1 represent in a normal distribution?
  7. How would you find P(z0.5)P(z \geq -0.5) using the z-table?
  8. What steps would you take to calculate P(z3.0)P(z \geq 3.0)?

Tip: For large positive z-scores, the area to the right becomes small, indicating rare events in a standard normal distribution.

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Math Problem Analysis

Mathematical Concepts

Normal distribution
Z-score
Probability calculations

Formulas

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Theorems

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Suitable Grade Level

Advanced High School / College