In a uniform distribution, all outcomes are equally likely within a given interval. If we assume that the random variable $X$ is uniformly distributed over the interval $[a, b]$, the probability density function (PDF) is constant within that interval and zero outside it.

For a uniform distribution, the probability $P(X \geq 0.8)$ can be found using the formula:

$P(X \geq 0.8) = \frac{b - 0.8}{b - a}$

Where:

• $a$ is the lower bound of the uniform distribution.
• $b$ is the upper bound of the uniform distribution.
• $0.8$ is the value for which we are calculating the probability.

Without the specific values of $a$ and $b$, I can’t provide the exact probability. However, if you provide the interval $[a, b]$ from the figure, I can compute $P(X \geq 0.8)$ accordingly.

Do you want to upload the figure or provide the values of $a$ and $b$?

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Here are some relative questions that extend this topic:

1. What is the total area under the PDF of a uniform distribution?
2. How is the mean of a uniform distribution calculated?
3. What is the variance of a uniform distribution?
4. Can you explain the significance of the cumulative distribution function (CDF) in uniform distributions?
5. How would the probability change if $X$ were normally distributed instead of uniformly?

Tip: For any continuous distribution, the area under the curve of the PDF between two points gives the probability that the variable falls within that interval.