Math Problem Statement

The present selling price of Article A after allowing a discount of 15% on its cost price, is the same as the present selling price of Article B after allowing a discount of 25% on its cost price. Earlier Ramesh had purchased 34 pieces of Article A and 32 pieces of Article B at 10% discount on its cost price for Rs. 33,480. What is the present selling price (in Rs.) of each article?

Solution

Let's define the variables for the problem:

  • Let the cost price of Article A be CAC_A.
  • Let the cost price of Article B be CBC_B.

Step 1: Relationship between selling prices

The selling price of Article A after a 15% discount on its cost price is: SA=CA0.15CA=0.85CAS_A = C_A - 0.15C_A = 0.85C_A

Similarly, the selling price of Article B after a 25% discount on its cost price is: SB=CB0.25CB=0.75CBS_B = C_B - 0.25C_B = 0.75C_B

It is given that the selling prices of Articles A and B are the same, so: 0.85CA=0.75CB0.85C_A = 0.75C_B From this equation, we can express CBC_B in terms of CAC_A: CB=0.850.75CA=1715CAC_B = \frac{0.85}{0.75}C_A = \frac{17}{15}C_A

Step 2: Cost of purchasing articles

Ramesh purchased 34 pieces of Article A and 32 pieces of Article B at a 10% discount on their cost prices. So the total cost paid by Ramesh is: Total cost=34×0.9CA+32×0.9CB=33,480\text{Total cost} = 34 \times 0.9C_A + 32 \times 0.9C_B = 33,480 Substituting CB=1715CAC_B = \frac{17}{15}C_A into this equation: 34×0.9CA+32×0.9×1715CA=33,48034 \times 0.9C_A + 32 \times 0.9 \times \frac{17}{15}C_A = 33,480 Simplifying this equation: 30.6CA+32×0.9×1715CA=33,48030.6C_A + 32 \times 0.9 \times \frac{17}{15}C_A = 33,480 30.6CA+32×1.02CA=33,48030.6C_A + 32 \times 1.02C_A = 33,480 30.6CA+32.64CA=33,48030.6C_A + 32.64C_A = 33,480 63.24CA=33,48063.24C_A = 33,480 CA=33,48063.24=529.35C_A = \frac{33,480}{63.24} = 529.35

Step 3: Calculate CBC_B

Now that we know CAC_A, we can find CBC_B: CB=1715×529.35=599.26C_B = \frac{17}{15} \times 529.35 = 599.26

Step 4: Calculate present selling prices

The present selling price of Article A is: SA=0.85×529.35=449.95S_A = 0.85 \times 529.35 = 449.95

The present selling price of Article B is: SB=0.75×599.26=449.45S_B = 0.75 \times 599.26 = 449.45

So, the present selling price of each article is approximately Rs. 450.


Would you like any further clarifications or details on this?

Here are 5 related questions you might find interesting:

  1. What would the selling price be if the discount for Article A was 20% instead of 15%?
  2. How much profit or loss did Ramesh make if he sold all articles at their present selling prices?
  3. What is the break-even price for both articles assuming no discount?
  4. If Ramesh had purchased more articles at a different discount rate, how would the overall cost change?
  5. How would the relationship between cost prices change if Article B had a different percentage discount?

Tip: Always double-check the interpretation of discounts, especially when solving cost and selling price problems involving multiple articles!

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Math Problem Analysis

Mathematical Concepts

Algebra
Percentage
Linear Equations

Formulas

Selling price after discount = Cost price - (Discount percentage × Cost price)
Total cost = Quantity × Discounted price

Theorems

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Suitable Grade Level

Grades 10-12