Math Problem Statement
You throw a nerf basketball of mass 0.002 kg into the air. At t = 0, the ball leaves your hand. At t = 0.10 s, the net force on the ball is
(-0.0184, -0.0224, 0) N, its velocity is (1.87, 0.84, 0) m/s, and its position is (0.325, 0.180, 0) m. (Besides the gravitational force by Earth, air also exerts a force on the ball.)
if rnew = (0.35872, 0.19232,0). then what will the new position be if t=0.12 s, the net force on the ball is now (-0.0138, -0.0197, 0) N. What will be its position at t = 0.14 s?
Solution
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Math Problem Analysis
Mathematical Concepts
Newton's Laws of Motion
Kinematics
Formulas
Newton's second law
Kinematic equations
Theorems
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Suitable Grade Level
Advanced High School
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