Math Problem Statement

Calculate P^9_2.

Solution

The mathematical expression provided is P29P^9_2, which represents a permutation. The formula for permutations is:

Prn=n!(nr)!P^n_r = \frac{n!}{(n-r)!}

Here, n=9n = 9 and r=2r = 2. Let's calculate it:

P29=9!(92)!=9!7!P^9_2 = \frac{9!}{(9-2)!} = \frac{9!}{7!}

Expanding the factorials:

P29=9×8×7!7!P^9_2 = \frac{9 \times 8 \times 7!}{7!}

Cancel 7!7!:

P29=9×8=72P^9_2 = 9 \times 8 = 72

Thus, P29=72P^9_2 = 72.

Would you like more details or have any questions?

Related Questions:

  1. What is the formula for combinations and how does it differ from permutations?
  2. Can you explain why the order of selection matters in permutations?
  3. How would PrnP^n_r change if r>nr > n, and why is it undefined?
  4. Can we calculate PrnP^n_r directly using a calculator, and how?
  5. How do permutations apply to real-life problems, such as arranging people in a line?

Tip:

When dealing with permutations, remember that the order of arrangement is important—this distinguishes it from combinations!

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Math Problem Analysis

Mathematical Concepts

Permutations
Factorial Calculation

Formulas

P^n_r = n! / (n - r)!

Theorems

Basic Permutation Formula

Suitable Grade Level

Grades 9-12