Math Problem Statement

One of the internal angles of the rhombus is 1200 and the short- er diagonal is 3.4 meters long. Find the perimeter of the rhombus

Solution

To find the perimeter of the rhombus, we need to use the properties of the rhombus and the information given:

  1. Internal Angle: One of the internal angles is 120120^\circ.
  2. Shorter Diagonal: The shorter diagonal d1d_1 is 3.43.4 meters.

Step 1: Use the diagonal properties of the rhombus

The diagonals of a rhombus bisect each other at right angles (90°). Let's denote:

  • d1d_1 as the shorter diagonal 3.43.4 meters.
  • d2d_2 as the longer diagonal (which we need to find).
  • ss as the side length of the rhombus.

Step 2: Relate the angle to the sides

The given internal angle is 120120^\circ. Since the diagonals bisect the angles of the rhombus, the angle between the diagonals will be half of 120120^\circ, which is 6060^\circ.

Step 3: Apply trigonometry to find the side length

Using the law of cosines in one of the triangles formed by the diagonals:

s2=(d12)2+(d22)2(d12)(d22)cos(120)s^2 = \left(\frac{d_1}{2}\right)^2 + \left(\frac{d_2}{2}\right)^2 - \left(\frac{d_1}{2}\right)\left(\frac{d_2}{2}\right)\cos(120^\circ)

However, knowing that cos(120)=12\cos(120^\circ) = -\frac{1}{2}, we simplify this further:

s2=(d12)2+(d22)2+(d1d24)s^2 = \left(\frac{d_1}{2}\right)^2 + \left(\frac{d_2}{2}\right)^2 + \left(\frac{d_1 \cdot d_2}{4}\right)

Given d1=3.4d_1 = 3.4 meters, we can simplify further to find d2d_2. First, let’s determine ss:

sin(1202)=sin(60)=32\sin\left(\frac{120^\circ}{2}\right) = \sin(60^\circ) = \frac{\sqrt{3}}{2}

Thus,

s=d12×sin(1202)=3.42×32=3.431.962 meterss = \frac{d_1}{2 \times \sin\left(\frac{120^\circ}{2}\right)} = \frac{3.4}{2 \times \frac{\sqrt{3}}{2}} = \frac{3.4}{\sqrt{3}} \approx 1.962\ \text{meters}

Step 4: Calculate the perimeter

The perimeter of a rhombus is 44 times the side length:

Perimeter=4×s4×1.962=7.848 meters\text{Perimeter} = 4 \times s \approx 4 \times 1.962 = 7.848\ \text{meters}

Final Answer

The perimeter of the rhombus is approximately 7.848 meters.

Do you want further details or have any questions?


Here are 5 relative questions for further exploration:

  1. How does changing the internal angle affect the perimeter of the rhombus?
  2. What is the relationship between the diagonals of a rhombus and its area?
  3. How would the perimeter change if the shorter diagonal were doubled?
  4. Can you determine the length of the longer diagonal d2d_2?
  5. What is the formula for finding the area of a rhombus using its diagonals?

Tip: In any rhombus, all sides are equal in length, but the angles can vary. This property can be useful in solving different types of problems involving rhombuses.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Trigonometry

Formulas

Law of Cosines

Theorems

Properties of Rhombus

Suitable Grade Level

Grades 9-12