Math Problem Statement

A farmer decided to fence a triangular vegetable garden from his field bounded on two sides by streets intersecting at 31°15′. The sides of the garden along the streets are 5 m and 10 m.

a.Find the perimeter of the garden.

b.Find the area of the garden.

c.Seedlings are to be planted in the garden at a cost of Php150 per square meter. What is the total cost?

Solution

We can solve this problem using trigonometry and geometry. Here's how:

Given Data:

  • The triangular garden is bounded on two sides by streets intersecting at an angle of 31°15′ (or 31.25° in decimal).
  • The sides along the streets are 5 m and 10 m.

Let's go through each part:


Part (a): Find the perimeter of the garden

We can use the Law of Cosines to find the third side of the triangle, cc, opposite to the angle 31°1531°15′.

The Law of Cosines formula is: c2=a2+b22abcos(θ)c^2 = a^2 + b^2 - 2ab \cdot \cos(\theta) where:

  • a=5ma = 5 \, \text{m}
  • b=10mb = 10 \, \text{m}
  • θ=31.25°\theta = 31.25°

Substitute the values: c2=52+1022×5×10×cos(31.25°)c^2 = 5^2 + 10^2 - 2 \times 5 \times 10 \times \cos(31.25°) Now, we calculate the third side cc and then the perimeter.


Part (b): Find the area of the garden

We can use the formula for the area of a triangle when two sides and the included angle are given: Area=12absin(θ)\text{Area} = \frac{1}{2}ab \sin(\theta) Substitute the values: Area=12×5×10×sin(31.25°)\text{Area} = \frac{1}{2} \times 5 \times 10 \times \sin(31.25°)


Part (c): Total cost for seedlings

The cost of planting seedlings is Php 150 per square meter. The total cost is calculated as: Total Cost=Area×Cost per square meter\text{Total Cost} = \text{Area} \times \text{Cost per square meter} Substitute the area found in part (b) and the cost per square meter: Total Cost=Area×150\text{Total Cost} = \text{Area} \times 150


Now, let's calculate these values.### Solutions:

Part (a): The perimeter of the garden is approximately:

Perimeter21.29meters\text{Perimeter} \approx 21.29 \, \text{meters}

Part (b): The area of the garden is approximately:

Area12.97square meters\text{Area} \approx 12.97 \, \text{square meters}

Part (c): The total cost of planting seedlings is approximately:

Total CostPhp1945.40\text{Total Cost} \approx \text{Php} 1945.40


Do you have any questions or need more details on any part?

Here are 5 related questions:

  1. How would the perimeter change if one side was increased by 2 meters?
  2. Can we find the angles of the triangle if the third side is known?
  3. What would be the cost if the price per square meter increased by 10%?
  4. How would the area calculation differ if the angle was larger than 90°?
  5. What other methods can we use to calculate the area of a triangle?

Tip: Knowing the Law of Cosines and Law of Sines helps solve triangles when angles and sides are involved!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Law of Cosines
Area of a Triangle
Perimeter

Formulas

c^2 = a^2 + b^2 - 2ab * cos(θ) (Law of Cosines)
Area = (1/2) * a * b * sin(θ) (Area of a triangle given two sides and an included angle)
Total Cost = Area * Cost per square meter

Theorems

Law of Cosines
Sine Rule for Area of a Triangle

Suitable Grade Level

Grades 10-12