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The problem asks to find the percentage of games won by the St. Paul High School basketball team, given that they won 15 games and lost 25 games.

### Step-by-step solution:

1. **Total games played**:
   The team played a total number of games, which is the sum of wins and losses:
   \[
   \text{Total games} = 15 + 25 = 40
   \]

2. **Percentage of games won**:
   The percentage of games won can be calculated as:
   \[
   \text{Percentage won} = \left(\frac{\text{Games won}}{\text{Total games}}\right) \times 100 = \left(\frac{15}{40}\right) \times 100 = 37.5\%
   \]

Thus, the percentage of games won by the school is **37.50%**.

Let me know if you would like further details or explanations!

Here are 5 related questions to expand on this:
1. If the team had won 20 games instead, what would their win percentage be?
2. How many games would the team need to win in a 50-game season to maintain the same 37.50% win rate?
3. What percentage of games did the team lose?
4. If another team won 22 games and lost 18, what would their win percentage be?
5. How would you calculate the win percentage if the number of games was not provided directly?

**Tip**: When calculating percentages, always ensure that the total value you're using includes all possible outcomes (in this case, both wins and losses).

Last season the St. Paul High School basketball team won 15 games and lost 25 games. What percent of the games were won by the school?

Determine the percentage of games won by the St. Paul High School basketball team after winning 15 games and losing 25. This math problem focuses on calculating percentages and ratios and is suitable for Grades 6-8.

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