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Let's work through the calculations step by step to correct your answers.

1. **Mass of recovered copper:**
   - The mass of the evaporating dish and recovered copper is **122.529 g**.
   - The mass of the empty evaporating dish is **122.189 g**.

   The **mass of recovered copper** is:

   \[
   \text{Mass of recovered copper} = 122.529\,\text{g} - 122.189\,\text{g} = 0.340\,\text{g}
   \]

   Update the mass of recovered copper to **0.340 g**.

2. **Percent recovery:**
   - The initial mass of copper is **0.131 g**.
   - The recovered mass of copper is now **0.340 g**.

   The formula for percent recovery is:

   \[
   \text{Percent recovery} = \left(\frac{\text{recovered mass}}{\text{initial mass}} \right) \times 100
   \]

   Substituting the values:

   \[
   \text{Percent recovery} = \left(\frac{0.340}{0.131} \right) \times 100 = 259.54\%
   \]

   The new percent recovery should be **259.5%** (rounded to one decimal place).

### Summary:
- Correct the **mass of recovered copper** to **0.340 g**.
- The **percent recovery** should be **259.5%**.

Do you need help with the final part about possible sources of error in this experiment? Here are 5 related questions to consider:

1. Why is it important to accurately subtract the mass of the evaporating dish when calculating the recovered mass of copper?
2. How could an error in measurement affect the percent recovery calculation?
3. What might cause the percent recovery to exceed 100%?
4. Should the number of significant figures in the mass measurements affect the precision of the final percent recovery?
5. What are some potential laboratory errors that could lead to inaccurate recovery of copper?

**Tip:** Ensure you're using consistent decimal places for measurements throughout the calculation to avoid rounding errors.

Learn how to calculate the percent recovery of copper in a chemistry lab experiment. This guide walks through subtracting the mass of the evaporating dish, calculating recovered copper, and using significant figures in the final percent recovery result. Suitable for Grades 9-12 students.

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