Math Problem Statement

Three identical metal spheres are hung from a ceiling on rigid non-conducting rods. Sphere 1, sphere 2, and sphere 3 have charges 31 µC,−50 µC, and 46 µC, respectively. Each sphere is separated by 11 cm. What is the net electric force on the middle sphere due to spheres 1 and 3? (Enter the magnitude only.)

Solution

To find the net electric force on the middle sphere (Sphere 2) due to Spheres 1 and 3, we need to use Coulomb's law. The force between two charged objects is given by:

F=keq1q2r2F = k_e \frac{|q_1 \cdot q_2|}{r^2}

Where:

  • FF is the magnitude of the force between the charges.
  • kek_e is Coulomb's constant, ke=8.99×109N m2/C2k_e = 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2.
  • q1q_1 and q2q_2 are the charges on the two spheres.
  • rr is the distance between the two charges.

Step 1: Calculate the force between Sphere 1 and Sphere 2

Given:

  • q1=31μC=31×106Cq_1 = 31 \, \mu C = 31 \times 10^{-6} \, C
  • q2=50μC=50×106Cq_2 = -50 \, \mu C = -50 \times 10^{-6} \, C
  • r12=11cm=0.11mr_{12} = 11 \, cm = 0.11 \, m

The force F12F_{12} between Sphere 1 and Sphere 2 is:

F12=keq1q2r122F_{12} = k_e \frac{|q_1 \cdot q_2|}{r_{12}^2}

Step 2: Calculate the force between Sphere 2 and Sphere 3

Given:

  • q2=50μC=50×106Cq_2 = -50 \, \mu C = -50 \times 10^{-6} \, C
  • q3=46μC=46×106Cq_3 = 46 \, \mu C = 46 \times 10^{-6} \, C
  • r23=11cm=0.11mr_{23} = 11 \, cm = 0.11 \, m

The force F23F_{23} between Sphere 2 and Sphere 3 is:

F23=keq2q3r232F_{23} = k_e \frac{|q_2 \cdot q_3|}{r_{23}^2}

Step 3: Determine the direction and net force

  • The force F12F_{12} will be attractive (towards Sphere 1) because Sphere 1 is positively charged and Sphere 2 is negatively charged.
  • The force F23F_{23} will also be attractive (towards Sphere 3) because Sphere 3 is positively charged and Sphere 2 is negatively charged.

Since both forces are in opposite directions along the same line, the net force FnetF_{net} on Sphere 2 is the difference between F23F_{23} and F12F_{12}.

Let's calculate the magnitudes of these forces.

I'll perform the calculations now.The net electric force on the middle sphere (Sphere 2) due to Spheres 1 and 3 is approximately 557.23 N.

Would you like further details or have any questions about the calculations? Here are some related questions to consider:

  1. How would the net force change if the distance between the spheres was doubled?
  2. What is the direction of the net force on Sphere 2?
  3. How would the net force on Sphere 2 be affected if the charges on Spheres 1 and 3 were reversed?
  4. What is the significance of the sign of the charges in determining the direction of the force?
  5. How does Coulomb’s law relate to Newton's law of gravitation?

Tip: Remember that the direction of the electric force depends on whether the interacting charges are like or unlike. Like charges repel, while unlike charges attract.

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Math Problem Analysis

Mathematical Concepts

Electrostatics
Coulomb's Law
Electric Force

Formulas

Coulomb's law: F = k_e * |q1 * q2| / r^2

Theorems

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Suitable Grade Level

College Level