Math Problem Statement
n = 2001
Solution
Given , let's calculate how many positive integers not exceeding 2001 are multiples of 3 or 4 but not 5.
Step 1: Calculate the relevant multiples
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Multiples of 3 up to 2001:
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Multiples of 4 up to 2001:
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Multiples of 12 up to 2001 (common multiples of 3 and 4):
Using the inclusion-exclusion principle:
Step 2: Subtract the multiples of 5
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Multiples of 5 up to 2001:
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Multiples of 15 up to 2001 (multiples of both 3 and 5):
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Multiples of 20 up to 2001 (multiples of both 4 and 5):
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Multiples of 60 up to 2001 (multiples of 3, 4, and 5):
Now, subtracting the multiples of 5:
Final Answer:
There are 801 positive integers not exceeding 2001 that are multiples of 3 or 4 but not 5.
Would you like more details or have any questions?
Here are 5 related questions:
- How would the count change if we considered numbers up to 5000?
- What would be the count if we included multiples of 6 as well?
- How does the inclusion-exclusion principle help avoid over-counting?
- Can you calculate the number of multiples of 3 and 4 but not multiples of 2?
- What is the significance of finding common multiples, like those of 12, 15, and 20, in this problem?
Tip: Double-check your work by re-evaluating edge cases, such as considering the largest multiple within the given range. This helps ensure accuracy, especially when using the inclusion-exclusion principle.
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Math Problem Analysis
Mathematical Concepts
Number Theory
Counting
Inclusion-Exclusion Principle
Formulas
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Theorems
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Suitable Grade Level
Grades 10-12
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