An automobile of mass 2,105 kg moves down the road with a speed of 21 m/s. What is the car's momentum, to the nearest kg⋅ms

The momentum of an object is given by the formula:

\[
p = m \cdot v
\]

where:
- \( p \) is the momentum,
- \( m \) is the mass of the object (in kilograms),
- \( v \) is the velocity of the object (in meters per second).

For the automobile:
- \( m = 2105 \, \text{kg} \),
- \( v = 21 \, \text{m/s} \).

Now, calculate the momentum:

\[
p = 2105 \, \text{kg} \times 21 \, \text{m/s} = 44,205 \, \text{kg} \cdot \text{m/s}.
\]

Thus, the car's momentum is approximately \( 44,205 \, \text{kg} \cdot \text{m/s} \).

Would you like more details or have any further questions?

Here are some related questions:
1. How does momentum change if the velocity doubles?
2. What is the difference between momentum and kinetic energy?
3. How is momentum conserved in a collision?
4. Can an object have momentum if its velocity is zero?
5. What happens to the momentum when the mass of an object is halved but its speed is doubled?

**Tip:** Momentum is a vector quantity, meaning it has both magnitude and direction. The direction of momentum is always the same as the velocity.

An automobile of mass 2,105 kg moves down the road with a speed of 21 m/s. What is the car's momentum, to the nearest kg⋅m/s?

Learn how to calculate the momentum of an automobile with a mass of 2,105 kg moving at a speed of 21 m/s. This problem uses the momentum formula p = m × v and is suitable for students in Grades 9-12 studying linear motion and basic physics concepts.

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