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To determine the moment of inertia \(I_x\) for the given cross-section (symmetrical I-beam), we can break the section into simpler geometric shapes, usually rectangles, and then apply the parallel axis theorem to calculate the total moment of inertia about the centroidal axis.

### Steps:
1. **Divide the section** into three parts:
   - **Flange 1 (top):** A rectangle of width 60 mm and height 20 mm.
   - **Flange 2 (bottom):** Another rectangle of width 120 mm and height 20 mm.
   - **Web (middle):** A vertical rectangle of width 20 mm and height 60 mm.

2. **Calculate the moment of inertia** for each part about their own centroidal axes:
   - For a rectangle, the moment of inertia about the centroidal axis (parallel to its base) is:
     \[
     I_{\text{rect}} = \frac{1}{12} \times \text{base} \times \text{height}^3
     \]
   - Apply this formula to each part.

3. **Use the parallel axis theorem** to shift the moment of inertia of the flanges to the centroidal axis of the entire section:
   \[
   I = I_{\text{centroid}} + A \cdot d^2
   \]
   where \(A\) is the area of the part, and \(d\) is the distance between the centroid of the part and the centroid of the entire section.

4. **Sum the contributions** from the web and the two flanges to get the total moment of inertia \(I_x\).

Let me calculate the values step by step.

### Geometry dataTo determine the moment of inertia \(I_x\) for the given cross-section (symmetrical I-beam), we can break the section into simpler geometric shapes, usually rectangles, and then apply the parallel axis theorem to calculate the total moment of inertia about the centroidal axis.

### Steps:
1. **Divide the section** into three parts:
   - **Flange 1 (top):** A rectangle of width 60 mm and height 20 mm.
   - **Flange 2 (bottom):** Another rectangle of width 120 mm and height 20 mm.
   - **Web (middle):** A vertical rectangle of width 20 mm and height 60 mm.

2. **Calculate the moment of inertia** for each part about their own centroidal axes:
   - For a rectangle, the moment of inertia about the centroidal axis (parallel to its base) is:
     \[
     I_{\text{rect}} = \frac{1}{12} \times \text{base} \times \text{height}^3
     \]
   - Apply this formula to each part.

3. **Use the parallel axis theorem** to shift the moment of inertia of the flanges to the centroidal axis of the entire section:
   \[
   I = I_{\text{centroid}} + A \cdot d^2
   \]
   where \(A\) is the area of the part, and \(d\) is the distance between the centroid of the part and the centroid of the entire section.

4. **Sum the contributions** from the web and the two flanges to get the total moment of inertia \(I_x\).

Let me calculate the values step by step.

### Geometry 
- **Flange 1**: 60 mm × 20 mm
- **Flange 2**: 120 mm × 20 mm
- **Web**: 20 mm × 60 mm
- Total height = 100 mm (20 mm + 60 mm + 20 mm)

Let me compute the moment of inertia \(I_x\).The total moment of inertia \(

Determine the moment of inertia Ix for the given symmetrical I-beam cross-section.

Learn how to calculate the moment of inertia (Ix) for a symmetrical I-beam cross-section using geometric principles and the Parallel Axis Theorem. This detailed guide covers the breakdown of the section into simpler shapes, calculation of individual moments of inertia, and application of the Parallel Axis Theorem for an accurate result. Suitable for engineering students and professionals.

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