8) Aspirin has the chemical formula C9H8O4. How many moles of aspirin would you need to have 10.0 g of carbon from 
the aspirin

To find how many moles of aspirin (C₉H₈O₄) contain 10.0 g of carbon, we'll go step by step:

### 1. Find the mass of carbon in one mole of aspirin:
- The chemical formula for aspirin is C₉H₈O₄, meaning each mole of aspirin contains 9 moles of carbon atoms.
- The atomic mass of carbon (C) is approximately 12.01 g/mol.

So, the mass of carbon in one mole of aspirin is:
\[
9 \, \text{mol} \times 12.01 \, \text{g/mol} = 108.09 \, \text{g of carbon per mole of aspirin}.
\]

### 2. Determine the fraction of carbon in aspirin:
We now know that for every mole of aspirin, there are 108.09 g of carbon. This helps us figure out how many moles of aspirin are needed to get 10.0 g of carbon.

### 3. Set up a proportion to find the moles of aspirin:
Let \( n \) be the number of moles of aspirin needed. Using the proportion:
\[
\frac{108.09 \, \text{g of carbon}}{1 \, \text{mol of aspirin}} = \frac{10.0 \, \text{g of carbon}}{n \, \text{mol of aspirin}}.
\]

Solving for \( n \):
\[
n = \frac{10.0 \, \text{g of carbon}}{108.09 \, \text{g/mol}} = 0.0925 \, \text{mol}.
\]

### Final Answer:
You would need approximately **0.0925 moles of aspirin** to have 10.0 g of carbon.

Would you like further details or have any questions? 

Here are 5 related questions for deeper understanding:
1. How would you calculate the mass of hydrogen in one mole of aspirin?
2. What is the molecular weight of aspirin (C₉H₈O₄)?
3. If you had 0.5 moles of aspirin, how much carbon would be present?
4. How many grams of oxygen are present in 2 moles of aspirin?
5. How do you find the number of molecules in a given number of moles of aspirin?

**Tip:** Always ensure units are consistent when calculating proportions to avoid errors.

Aspirin has the chemical formula C9H8O4. How many moles of aspirin would you need to have 10.0 g of carbon from the aspirin?

Find out how many moles of aspirin (C9H8O4) you need to get 10.0 g of carbon. Learn about stoichiometry, mole calculations, and proportions with a step-by-step explanation. Suitable for students in Grades 10-12.

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