An 85.00 g sample of an unknown compound contains 24.26 g molybdenum, 24.33 g sulfur, and the rest is oxygen.

What quantity in moles of molybdenum are present in the compound?

To find the quantity of moles of molybdenum in the unknown compound, we will use the molar mass of molybdenum (Mo).

### Step 1: Find the molar mass of molybdenum (Mo).
- The molar mass of molybdenum (Mo) is 95.95 g/mol.

### Step 2: Calculate the number of moles of molybdenum.
We can use the formula:

\[
\text{moles of Mo} = \frac{\text{mass of Mo}}{\text{molar mass of Mo}}
\]

Given:
- Mass of molybdenum (Mo) = 24.26 g
- Molar mass of Mo = 95.95 g/mol

\[
\text{moles of Mo} = \frac{24.26}{95.95} = 0.2528 \, \text{moles}
\]

Thus, the quantity of moles of molybdenum present in the compound is approximately **0.2528 moles**.

Would you like to go over more details or ask any questions?

### Related Questions:
1. How do you calculate the moles of sulfur in the compound?
2. What is the mass of oxygen in the compound?
3. How do you determine the empirical formula of the compound?
4. How does molar mass influence mole calculations in compounds?
5. How would you find the moles of oxygen if the mass is known?

### Tip: 
Always ensure you use the correct molar masses when calculating moles from masses in chemical reactions or compounds.

An 85.00 g sample of an unknown compound contains 24.26 g molybdenum, 24.33 g sulfur, and the rest is oxygen. What quantity in moles of molybdenum are present in the compound?

Learn how to calculate the moles of molybdenum in a compound containing 24.26 g molybdenum. This solution covers stoichiometry and the mole concept, using the formula moles = mass / molar mass. Suitable for high school chemistry students in Grades 10-12.

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