If 29.24 ml of 2.215 M NaOH solution reacts with 11.8 ml of phosphorous acid solution.  What is the molarity of the phosphorous acid solution?   

Enter to 4 decimal places



To find the molarity of the phosphorous acid (H₃PO₃) solution, we can follow these steps:

1. **Balanced chemical equation**: Phosphorous acid (H₃PO₃) reacts with sodium hydroxide (NaOH) in the following reaction:
   \[
   \text{H₃PO₃} + 2\text{NaOH} \rightarrow \text{Na₂HPO₃} + 2\text{H₂O}
   \]
   In this reaction, 1 mole of H₃PO₃ reacts with 2 moles of NaOH.

2. **Moles of NaOH**: Using the given molarity and volume of the NaOH solution, calculate the moles of NaOH:
   \[
   \text{Moles of NaOH} = M_{\text{NaOH}} \times V_{\text{NaOH}} = 2.215 \, \text{M} \times 0.02924 \, \text{L}
   \]
   Let's calculate this first.

\[
\text{Moles of NaOH

If 29.24 ml of 2.215 M NaOH solution reacts with 11.8 ml of phosphorous acid solution, what is the molarity of the phosphorous acid solution? Enter to 4 decimal places.

Find the molarity of phosphorous acid (H₃PO₃) when reacting with NaOH using stoichiometric principles. This solution involves key concepts like molarity, chemical reactions, and stoichiometry, ideal for high school chemistry students.

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