the molar mass of sucrose is 342.2965 g/mol

The molar mass of sucrose is indeed 342.2965 g/mol. This value is derived from the molecular formula of sucrose, which is \( \text{C}_{12}\text{H}_{22}\text{O}_{11} \). To calculate this, you sum the atomic masses of all the atoms in one molecule of sucrose:

- Carbon (C): \( 12 \times 12.011 = 144.132 \, \text{g/mol} \)
- Hydrogen (H): \( 22 \times 1.008 = 22.176 \, \text{g/mol} \)
- Oxygen (O): \( 11 \times 15.999 = 175.989 \, \text{g/mol} \)

Adding these together gives:

\[
144.132 + 22.176 + 175.989 = 342.297 \, \text{g/mol}
\]

This rounds to the reported molar mass of 342.2965 g/mol.

Would you like more details or have any questions?

Here are 5 related questions you might find interesting:
1. How do you calculate the number of moles in a given mass of sucrose?
2. What is the mass of 0.5 moles of sucrose?
3. How does the molecular structure of sucrose affect its molar mass?
4. What is the role of molar mass in stoichiometry?
5. How can you experimentally determine the molar mass of a compound?

**Tip:** Remember that the precision of the molar mass can affect the accuracy of calculations in stoichiometry and solution preparation.

Understand how to calculate the molar mass of sucrose (C12H22O11) using atomic masses of carbon, hydrogen, and oxygen. Detailed step-by-step explanation with the final molar mass rounded to 342.2965 g/mol. Suitable for advanced high school students and beyond.

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