To solve this problem, let's focus on the required space to hang the three prints.

Each print has dimensions of 3 inches by 5 inches, and the prints will be arranged vertically. There is a 1-inch space between each print.

To find the minimum wall space Jo Lee needs, consider the following:

1. Height of the space: The three prints each have a height of 3 inches, so the total height for the three prints is: $3 \text{ in} + 3 \text{ in} + 3 \text{ in} = 9 \text{ in}$ Additionally, there are two 1-inch spaces between the prints, so the total space between the prints is: $1 \text{ in} + 1 \text{ in} = 2 \text{ in}$ Thus, the total height required is: $9 \text{ in} + 2 \text{ in} = 11 \text{ in}$

2. Width of the space: Since the prints are hung vertically, the width required for each print is 5 inches. The total width of the space is just the width of one print: $5 \text{ in}$

Therefore, the minimum wall space Jo Lee must have is 11 inches by 5 inches.

The area of this space can be calculated as: $11 \text{ in} \times 5 \text{ in} = 55 \text{ sq in}$

However, it seems like the available answer choices don’t exactly match this calculation. There might be an oversight, or the problem could be asking for something different in the context (perhaps the space excluding or including a specific arrangement). Let me know if you would like further clarification or if there's another aspect to consider.

Would you like more details or to clarify any part of this? Here are 5 related questions for further practice:

1. How does the arrangement of prints affect the total space needed on the wall?
2. What is the formula for the area of a rectangle?
3. If the prints were arranged horizontally, how would the total space change?
4. How can you calculate the space needed for multiple objects arranged with a gap between them?
5. What other real-world problems can be solved using area calculations like this?

Tip: Always double-check if the problem asks for the area of the total space or just one dimension.