Math Problem Statement

If friction accounts for 12% of the load per sheave, find the minimum size of nylon rope that can be used in a watch tackle to lift a weight of 3.5 lonnes.

Solution

To determine the minimum size of nylon rope required to lift a weight of 3.5 tonnes using a watch tackle, accounting for frictional losses, we need to go through a few key steps.

Given Information:

  • Weight to lift: 3.5 tonnes (equivalent to 3500 kg)
  • Friction loss: 12% of the load per sheave (pulley)

Step 1: Calculate the total force required, including friction losses.

If 12% of the load is lost per sheave, we need to consider how many pulleys (sheaves) are in the system. However, the total friction force will be additive based on the number of pulleys. Let's assume nn pulleys.

Each sheave adds an additional force requirement equal to 12%12\% of the current load.

  • Force required for one pulley: Force on one sheave=3500×1.12=3920kg\text{Force on one sheave} = 3500 \times 1.12 = 3920 \, \text{kg}

  • For nn pulleys, the force would increase depending on how many pulleys are present. If there are multiple pulleys, we'd adjust this accordingly.

Step 2: Determine the

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Mechanical Advantage
Force Calculation
Percentage of Load Loss due to Friction

Formulas

Total Force = Weight × (1 + Friction Percentage)
Force per Sheave = Load × (1 + Friction Percentage per Sheave)

Theorems

Mechanical Advantage Theorem

Suitable Grade Level

Grades 10-12