Math Problem Statement
Recently, a random sample of 25-34 year olds was asked, "How much do you currently have in savings, not including retirement savings?" The data in the table represent the responses to the survey. Approximate the mean and standard deviation amount of savings.
Solution
To calculate the approximate mean and standard deviation of the savings amounts from the data provided, we'll need to follow these steps:
1. Midpoint Calculation:
For each savings range, calculate the midpoint. The midpoint () of each class interval is calculated as:
2. Mean Calculation:
The mean () is calculated using the formula: Where:
- is the frequency of each class interval.
- is the midpoint of each class interval.
3. Standard Deviation Calculation:
The standard deviation () is calculated using the formula:
Now let's proceed with these calculations using the provided dataTo calculate the approximate mean and standard deviation of the savings amounts from the data provided, we'll need to follow these steps:
1. Midpoint Calculation:
For each savings range, calculate the midpoint. The midpoint () of each class interval is calculated as:
2. Mean Calculation:
The mean () is calculated using the formula: Where:
- is the frequency of each class interval.
- is the midpoint of each class interval.
3. Standard Deviation Calculation:
The standard deviation () is calculated using the formula:
Now let's proceed with these calculations using the provided
Savings | Frequency () | Midpoint () |
---|---|---|
$0 - $199 | 349 | |
$200 - $399 | 93 | |
$400 - $599 | 57 | |
$600 - $799 | 16 | |
$800 - $999 | 10 | |
$1000 - $1199 | 6 | |
$1200 - $1399 | 4 |
Let me now compute the mean and standard deviation.The approximate mean amount of savings is $229.97. The standard deviation is $227.35.
Would you like more details or have any questions? Here are some related questions:
- How does the standard deviation help in understanding the distribution of savings?
- What is the significance of using midpoints in this calculation?
- How would the mean and standard deviation change if one of the frequencies increased?
- What are the implications of a low versus high standard deviation in financial data like savings?
- How would the calculations differ if the intervals were not equal in width?
Tip: Understanding the standard deviation helps you grasp how spread out the savings amounts are around the mean, which is crucial for financial planning and analysis.
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Math Problem Analysis
Mathematical Concepts
Statistics
Descriptive Statistics
Formulas
Midpoint = (Lower limit + Upper limit) / 2
Mean (μ) = Σ(f_i * x_i) / Σf_i
Standard Deviation (σ) = sqrt(Σf_i * (x_i - μ)^2 / Σf_i)
Theorems
Standard Deviation
Suitable Grade Level
Grades 9-12
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