Math Problem Statement

25

24

26

24

31

30

29

27

34

30

25

37

26

24

23

28

29

26

32

30

26

23

32

30

23

29

28

27

24

22

26

22

26

25

23

27

26

33

27

30

Solution

Let's calculate the mean, median, and mode for the given ages.

The provided ages are: 25,24,26,24,31,30,29,27,34,30,25,37,26,24,23,28,29,26,32,30,26,23,32,30,23,29,28,27,24,22,26,22,26,25,23,27,26,33,27,3025, 24, 26, 24, 31, 30, 29, 27, 34, 30, 25, 37, 26, 24, 23, 28, 29, 26, 32, 30, 26, 23, 32, 30, 23, 29, 28, 27, 24, 22, 26, 22, 26, 25, 23, 27, 26, 33, 27, 30

1. Mean (Average)

To calculate the mean, we sum all the ages and divide by the number of ages.

Mean=Sum of all agesNumber of ages\text{Mean} = \frac{\text{Sum of all ages}}{\text{Number of ages}}

2. Median

To find the median, we first sort the ages in ascending order. Then, we find the middle value(s).

3. Mode

The mode is the most frequently occurring age in the list.

Let's perform these calculations.Here are the calculated values for the given ages:

  1. Mean (Average): 27.225 years
  2. Median: 26.5 years
  3. Mode: 26 years (the most frequently occurring age)

Would you like more details or have any questions?

Additional Questions:

  1. How are mean, median, and mode useful in data analysis?
  2. What happens if there are multiple modes in a dataset?
  3. Can the mean and median be the same? When does that happen?
  4. How does the presence of outliers affect the mean, median, and mode?
  5. Why is the median often preferred over the mean in skewed data?

Tip: In a dataset with outliers or skewed distribution, the median can provide a better measure of central tendency than the mean.