https://file.aiquickdraw.com/mathbot/file/17294856591604j6ha61u.jpg

Let's calculate the mean, median, and mode of Thao's scores: 79, 83, 45, 87, 79, and 91.

### 1. Mean:
The mean is the average of the numbers, calculated as:

\[
\text{Mean} = \frac{\text{Sum of all values}}{\text{Number of values}}
\]

\[
\text{Sum of values} = 79 + 83 + 45 + 87 + 79 + 91 = 464
\]

\[
\text{Mean} = \frac{464}{6} = 77.33
\]

So, the mean is **77.33**.

### 2. Median:
The median is the middle number when the values are arranged in order. First, arrange the scores in ascending order:

\[
45, 79, 79, 83, 87, 91
\]

Since there is an even number of scores (6), the median is the average of the two middle numbers (79 and 83):

\[
\text{Median} = \frac{79 + 83}{2} = 81
\]

So, the median is **81**.

### 3. Mode:
The mode is the number that appears most frequently. In this case, **79** appears twice, while all other scores appear only once.

Thus, the mode is **79**.

---

Would you like any further clarification or details on these calculations?

Here are some related questions you could explore:
1. How would these statistics change if another score was added?
2. What if we had to find the range of these scores?
3. How do outliers affect the mean and median?
4. Could a set of scores have more than one mode?
5. What would happen to the mode if 79 appeared even more frequently?

**Tip:** Always arrange the data set in ascending order before finding the median!

Find the mean, the median, and the mode for Thao's scores: 79, 83, 45, 87, 79, and 91.

Learn how to calculate the mean, median, and mode for a set of exam scores: 79, 83, 45, 87, 79, and 91. This detailed solution walks you through each step, including sorting the scores, computing the average, finding the middle value, and identifying the most frequent score. Suitable for students in Grades 5-7.

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