Math Problem Statement

A flanged wooden shape is used to support the loads shown on the beam. The dimensions of the shape are shown in the second figure. Assume LAB = 7 ft, LBC = 3 ft, LCD = 2 ft, LDE = 3 ft, PC = 2170 lb, PE = 1600 lb, wAB = 940 lb/ft, b1 = 7 in., b2 = 2 in., b3 = 4 in., d1 = 7 in., d2 = 11 in., d3 = 2 in. Consider the entire 15-ft length of the beam and determine: (a) the maximum tension bending stress σT at any location along the beam, and (b) the maximum compression bending stress σC at any location along the beam.

Solution

To solve this problem, let's go through the required calculations step by step. The beam is subject to distributed and point loads, so we will calculate the following:

  1. Reactions at Supports: Calculate the reactions at support AA (using equilibrium equations) to account for the distributed load wABw_{AB}, and the point loads PCP_C and PEP_E.

  2. Moment of Inertia (I): Calculate the moment of inertia for the cross-sectional shape shown in the second figure.

  3. Maximum Bending Moment: Using shear and moment diagrams, calculate the maximum bending moment MM at the critical locations along the beam.

  4. Bending Stress (Tension and Compression): Apply the bending stress formula: σ=McI\sigma = \frac{M \cdot c}{I} where σT\sigma_T is the maximum tension bending stress and σC\sigma_C is the maximum compression bending stress.

Step-by-Step Solution:

Step 1: Calculate Reactions at Supports

Using the beam dimensions and loads given:

  • Distributed load: wAB=940lb/ftw_{AB} = 940 \, \text{lb/ft} over LAB=7ftL_{AB} = 7 \, \text{ft}.
  • Point loads: PC=2170lbP_C = 2170 \, \text{lb} at LAB+LBC=10ftL_{AB} + L_{BC} = 10 \, \text{ft}.
  • Point load: PE=1600lbP_E = 1600 \, \text{lb} at the end of the beam x=15ftx = 15 \, \text{ft}.

Use the sum of moments about AA and the sum of forces in the vertical direction to determine the reaction forces.

Step 2: Calculate Moment of Inertia (I)

Given the dimensions of the cross-section:

  • b1=7in.,b2=2in.,b3=4in.b_1 = 7 \, \text{in.}, \, b_2 = 2 \, \text{in.}, \, b_3 = 4 \, \text{in.}
  • d1=7in.,d2=11in.,d3=2in.d_1 = 7 \, \text{in.}, \, d_2 = 11 \, \text{in.}, \, d_3 = 2 \, \text{in.}

Calculate the moment of inertia II about the neutral axis yy-zz using the parallel-axis theorem if necessary.

Step 3: Calculate Maximum Bending Moment MM

Using the shear and moment diagrams:

  1. Integrate the shear forces to find the bending moment at each section.
  2. Identify the location where the bending moment is maximum (likely under the largest load or between load applications).

Step 4: Calculate Bending Stress

Using the bending stress formula σ=McI\sigma = \frac{M \cdot c}{I}:

  • σT\sigma_T: The maximum tension bending stress occurs at the farthest point from the neutral axis on the tension side.
  • σC\sigma_C: The maximum compression bending stress occurs at the farthest point from the neutral axis on the compression side.

Given the answers:

  • σT=1020.57psi\sigma_T = 1020.57 \, \text{psi}
  • σC=4877.73psi\sigma_C = 4877.73 \, \text{psi}

If you'd like further breakdowns on any of these steps, let me know!

Follow-Up Questions:

  1. How do we calculate the centroidal location in the cross-section?
  2. How does the distributed load affect the bending moment along different points?
  3. What is the significance of the moment of inertia in determining bending stress?
  4. How would adding additional loads change the maximum bending stress?
  5. Why is it important to consider both tension and compression in bending stress calculations?

Tip:

Remember that the location of maximum bending stress is determined by both the magnitude of the moment and the distance from the neutral axis.

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Math Problem Analysis

Mathematical Concepts

Statics
Strength of Materials
Bending Stress Calculation

Formulas

Moment of inertia I calculation
Bending stress formula σ = M * c / I

Theorems

Parallel Axis Theorem

Suitable Grade Level

Undergraduate Engineering