Math Problem Statement

The Enterprise goes into orbit around a mysterious planet. The ship moves at 4200 m/s in a circle of radius 4.91 x 10^7 m. What is the mass of the planet?

Solution

To determine the mass of the planet, we can use the formula for gravitational force providing the centripetal force for an object in circular orbit:

v2=GMrv^2 = \frac{G M}{r}

where:

  • vv is the orbital speed of the object,
  • GG is the gravitational constant (6.674×1011Nm2/kg26.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2),
  • MM is the mass of the planet,
  • rr is the radius of the orbit.

Rearranging this formula to solve for MM:

M=v2rGM = \frac{v^2 \cdot r}{G}

Given values:

  • v=4200m/sv = 4200 \, \text{m/s}
  • r=4.91×107mr = 4.91 \times 10^7 \, \text{m}
  • G=6.674×1011Nm2/kg2G = 6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2

Calculations:

  1. Calculate v2v^2: v2=42002=17640000m2/s2v^2 = 4200^2 = 17640000 \, \text{m}^2/\text{s}^2

  2. Substitute values into the equation for MM: M=17640000×4.91×1076.674×1011M = \frac{17640000 \times 4.91 \times 10^7}{6.674 \times 10^{-11}}

  3. Simplify the calculation.

Let's work through this.The mass of the planet is approximately 1.30×10251.30 \times 10^{25} kg.

Would you like further details or have any questions?

Related Questions:

  1. How would the mass calculation change if the orbit radius increased?
  2. What is the effect of a higher orbital velocity on the required mass?
  3. How does gravitational force impact objects in orbit?
  4. What would happen to the ship’s orbit if it slowed down?
  5. Can this method be used to calculate the mass of moons or satellites?

Tip: Remember that the gravitational constant GG is essential for calculations involving mass and gravity.

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Math Problem Analysis

Mathematical Concepts

Gravitational Force
Centripetal Force
Orbital Mechanics

Formulas

M = (v^2 * r) / G

Theorems

Newton's Law of Universal Gravitation

Suitable Grade Level

Grades 11-12