Here’s the solution to the given problems:

2a:

The mass of each packet is 150 g, and there are 10 packets in a box. Therefore: $\text{Total mass of 10 packets} = 150 \times 10 = 1500 \, \text{g} = 1.5 \, \text{kg}.$ Since the label states the mass is 1 kg, the label is not correct because the actual mass of the 10 packets is 1.5 kg, which is greater than 1 kg.

2b:

If there are 100 boxes of nuts in the store and each box weighs 1.5 kg (from part a), the total mass is: $\text{Total mass} = 1.5 \, \text{kg} \times 100 = 150 \, \text{kg}.$ So, the total mass of the nuts in the store is 150 kg.

3:

The total milk sold is 55,500 mL. To find the greatest possible number of 1-litre (1000 mL) milk cartons sold, we maximize their usage.

Step 1: Divide 55,500 mL by 1000 mL (1 litre):

$\text{Number of 1-litre cartons} = \left\lfloor \frac{55,500}{1000} \right\rfloor = 55.$ This leaves a remainder: $\text{Remaining milk} = 55,500 - (55 \times 1000) = 500 \, \text{mL}.$

Step 2: Check 500 mL cartons:

The remaining 500 mL can be packaged in one 500-mL carton.

Final Answer:

The greatest possible number of 1-litre cartons sold is 55, with one 500-mL carton used for the leftover.

Do you have any questions about these solutions? Would you like detailed explanations for any part?

Related Questions:

1. What would be the total mass of nuts in the store if each packet weighed 200 g instead of 150 g?
2. How would you find the total milk sold if 500-mL cartons were used exclusively?
3. What would the label need to state to be correct for the mass of 10 packets of nuts?
4. How would the total mass of nuts change if the store stocked 200 boxes instead of 100?
5. What percentage of the milk sold is in 1-litre cartons?

Tip:

Always ensure unit consistency when solving real-life problems involving weights and measures!