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To solve this problem, we need to calculate the mass of lidocaine in a 6.0 mL solution with a concentration of 1.0% \( \text{(w/v)} \).

### Step-by-Step Solution:

1. **Interpret the concentration**: A 1.0% \( \text{(w/v)} \) solution means there are 1.0 grams of lidocaine per 100 mL of solution.

2. **Set up the proportion** to find the mass of lidocaine in 6.0 mL:
   \[
   \frac{1.0 \, \text{g}}{100 \, \text{mL}} = \frac{x \, \text{g}}{6.0 \, \text{mL}}
   \]

3. **Solve for \( x \)**:
   \[
   x = \frac{1.0 \, \text{g} \times 6.0 \, \text{mL}}{100 \, \text{mL}} = 0.06 \, \text{g}
   \]

### Answer:
The mass of lidocaine in 6.0 mL of this solution is:
\[
\text{0.06 g}
\]

This value has two significant figures, which matches the precision of the given data.

Would you like a further breakdown or have any questions?

### Related Questions:
1. How would you calculate the mass of lidocaine in 10 mL of this solution?
2. What would be the mass of lidocaine in a 2.0% \( \text{(w/v)} \) solution for 6.0 mL?
3. How can you express this concentration in terms of molarity if the molar mass of lidocaine is known?
4. What is the difference between \( \text{(w/v)} \) and \( \text{(v/v)} \) solutions?
5. How would you prepare 1 L of a 0.5% \( \text{(w/v)} \) lidocaine solution?

### Tip:
For \( \text{(w/v)} \) solutions, remember that the percentage value directly gives you grams per 100 mL, which simplifies calculations when working with small volumes.

Calculate the mass of lidocaine in 6.0 mL of a 1.0% (w/v) solution for injection.

Learn how to calculate the mass of lidocaine in a 6.0 mL sample of a 1.0% (w/v) solution. This problem involves understanding proportions and concentration percentages, suitable for high school chemistry students.

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