Let's solve the problem step by step.

Part (a) - Finding the mass of the airplane:

We are given:

• The force exerted by the tractor on the pavement: $F_{\text{tractor}} = 1.95 \times 10^4 \, \text{N}$.
• The total resistive forces acting on the system: $F_{\text{resist}} = 2400 \, \text{N}$.
• The acceleration of the system: $a = 0.100 \, \text{m/s}^2$.
• The mass of the tractor: $m_{\text{tractor}} = 1800 \, \text{kg}$.

Now, to find the mass of the airplane, we'll apply Newton's second law to the system as a whole. The net force $F_{\text{net}}$ acting on the system is given by the difference between the force exerted by the tractor and the resistive forces: $F_{\text{net}} = F_{\text{tractor}} - F_{\text{resist}} = 1.95 \times 10^4 \, \text{N} - 2400 \, \text{N} = 1.71 \times 10^4 \, \text{N}$

From Newton's second law $F_{\text{net}} = (m_{\text{tractor}} + m_{\text{airplane}}) \times a$, we can solve for the mass of the airplane $m_{\text{airplane}}$:

$1.71 \times 10^4 \, \text{N} = (1800 \, \text{kg} + m_{\text{airplane}}) \times 0.100 \, \text{m/s}^2$

Solving for $m_{\text{airplane}}$:

$m_{\text{airplane}} = \frac{1.71 \times 10^4 \, \text{N}}{0.100 \, \text{m/s}^2} - 1800 \, \text{kg}$

$m_{\text{airplane}} = 171000 \, \text{kg} - 1800 \, \text{kg}$

$m_{\text{airplane}} = 169200 \, \text{kg}$

So, the mass of the airplane is 169200 kg.

Part (b) - Finding the force exerted by the tractor on the airplane:

We are given:

• The friction experienced by the airplane: $F_{\text{friction}} = 2000 \, \text{N}$.

We need to find the force exerted by the tractor on the airplane. Using Newton's second law for the airplane alone:

$F_{\text{tractor on airplane}} - F_{\text{friction}} = m_{\text{airplane}} \times a$

Substituting the values we know:

$F_{\text{tractor on airplane}} - 2000 \, \text{N} = 169200 \, \text{kg} \times 0.100 \, \text{m/s}^2$

$F_{\text{tractor on airplane}} - 2000 \, \text{N} = 16920 \, \text{N}$

Solving for $F_{\text{tractor on airplane}}$:

$F_{\text{tractor on airplane}} = 16920 \, \text{N} + 2000 \, \text{N}$

$F_{\text{tractor on airplane}} = 18920 \, \text{N}$

Thus, the force exerted by the tractor on the airplane is 18920 N.

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Let me know if you need any details or have further questions!

Here are 5 questions that expand upon this topic:

1. How would the force change if the resistive forces acting on the system increased?
2. What happens to the acceleration if the mass of the airplane increases while keeping the tractor's force constant?
3. How does the system behave if the friction experienced by the airplane doubles?
4. How would the tractor’s force change if the acceleration increased to 0.200 m/s²?
5. What is the significance of knowing the force of friction in systems like this?

Tip: Always ensure to subtract resistive forces when calculating net force in problems involving motion!