The magnitude of a vector can be found using the Pythagorean theorem. For a vector with components $B_x$ and $B_y$, the magnitude $|B|$ is given by:

$|B| = \sqrt{B_x^2 + B_y^2}$

Substituting the given values:

$B_x = -96.0 \, \text{m}, \, B_y = -78.9 \, \text{m}$

Now calculate the magnitude:

$|B| = \sqrt{(-96.0)^2 + (-78.9)^2}$ $|B| = \sqrt{9216 + 6224.01} = \sqrt{15440.01} \approx 124.3 \, \text{m}$

So, the magnitude of the vector is approximately 124.3 meters.

Would you like more details or have any other questions?

Here are 5 related questions:

1. What is the direction of the vector?
2. How do vector magnitudes change if both components are positive?
3. Can vectors have a negative magnitude?
4. How do you find the components of a vector given its magnitude and direction?
5. How do vector magnitudes behave in three dimensions?

Tip: The magnitude of a vector is always non-negative, regardless of the signs of its components.