B x equals negative 96.0 meters and  B y equals negative 78.9 meters. Find the magnitude of the vector. Blank meters; fill in the blank.

The magnitude of a vector can be found using the Pythagorean theorem. For a vector with components \( B_x \) and \( B_y \), the magnitude \( |B| \) is given by:

\[
|B| = \sqrt{B_x^2 + B_y^2}
\]

Substituting the given values:

\[
B_x = -96.0 \, \text{m}, \, B_y = -78.9 \, \text{m}
\]

Now calculate the magnitude:

\[
|B| = \sqrt{(-96.0)^2 + (-78.9)^2}
\]
\[
|B| = \sqrt{9216 + 6224.01} = \sqrt{15440.01} \approx 124.3 \, \text{m}
\]

So, the magnitude of the vector is approximately **124.3 meters**.

Would you like more details or have any other questions?

Here are 5 related questions:
1. What is the direction of the vector?
2. How do vector magnitudes change if both components are positive?
3. Can vectors have a negative magnitude?
4. How do you find the components of a vector given its magnitude and direction?
5. How do vector magnitudes behave in three dimensions?

**Tip:** The magnitude of a vector is always non-negative, regardless of the signs of its components.

B x equals negative 96.0 meters and B y equals negative 78.9 meters. Find the magnitude of the vector. Blank meters; fill in the blank.

Learn how to calculate the magnitude of a vector with components B_x = -96.0 meters and B_y = -78.9 meters using the Pythagorean theorem. Follow the step-by-step solution to find the magnitude of the vector as approximately 124.3 meters. Suitable for students in Grades 9-12.

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