Math Problem Statement

A shopkeeper increase price by 40% and give discount of 40% but measure 15%less.find loss and gain

Solution

To solve this problem, we need to break it down into parts:

  1. Price Increase and Discount:

    Let's assume the original price of the item is PP.

    • After a 40% increase, the new price becomes P×1.40P \times 1.40.
    • Then, a 40% discount is applied to the increased price, making the final price (P×1.40)×0.60=P×0.84(P \times 1.40) \times 0.60 = P \times 0.84.

    So, after increasing the price by 40% and then giving a 40% discount, the effective price becomes 84% of the original price PP.

  2. Measuring 15% Less:

    When the shopkeeper measures 15% less, it means they are giving only 85% of the actual quantity.

    If the original quantity is QQ, the given quantity is Q×0.85Q \times 0.85.

  3. Finding Loss or Gain:

    Now, let's determine the effective cost per unit for the shopkeeper and the customer:

    • Shopkeeper's perspective: They sell Q×0.85Q \times 0.85 quantity at the price of P×0.84P \times 0.84.
    • The effective price per unit for the shopkeeper is P×0.84Q×0.85=0.84P0.85Q\frac{P \times 0.84}{Q \times 0.85} = \frac{0.84P}{0.85Q}.

    Simplifying this, we get:

    0.84P0.85Q=84P85Q\frac{0.84P}{0.85Q} = \frac{84P}{85Q}

    • The original price per unit was PQ\frac{P}{Q}.

    To find the percentage loss or gain:

    Effective price per unit=8485×PQ\text{Effective price per unit} = \frac{84}{85} \times \frac{P}{Q}

    • Comparing this to the original price per unit PQ\frac{P}{Q}:

    Loss/Gain Percentage=(18485)×100%\text{Loss/Gain Percentage} = \left(1 - \frac{84}{85}\right) \times 100\%

    Simplifying this:

    Loss/Gain Percentage=(10.9882)×100%=1.1765% loss\text{Loss/Gain Percentage} = \left(1 - 0.9882\right) \times 100\% = 1.1765\% \text{ loss}

Thus, the shopkeeper experiences approximately a 1.18% loss.

Would you like further details or have any questions? Here are some more questions you can ask:

  1. How would the calculations change if the discount was 30% instead of 40%?
  2. What if the shopkeeper measures 10% less instead of 15%?
  3. How does changing the percentage of price increase affect the overall loss/gain?
  4. Can you explain how the price increase and discount interact mathematically?
  5. How do these types of pricing strategies affect consumer perception?

Tip: When dealing with percentage changes, remember that sequential percentage increases and decreases do not simply cancel each other out.

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Math Problem Analysis

Mathematical Concepts

Percentage Increase
Percentage Decrease
Profit and Loss

Formulas

Percentage change formula

Theorems

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Suitable Grade Level

Grades 7-9