To find the load that the column can support, we can use the relationship between stress and load:

$\text{Stress} = \frac{\text{Load}}{\text{Area}}$

Rearranging this to find the load:

$\text{Load} = \text{Stress} \times \text{Area}$

Given:

• Allowable tensile stress: $62,055 \, \text{kPa}$
• Cross-sectional area: $0.090 \, \text{m}^2$

First, convert the stress from $\text{kPa}$ to $\text{N/m}^2$ since $1 \, \text{kPa} = 1,000 \, \text{N/m}^2$:

$\text{Stress} = 62,055 \, \text{kPa} = 62,055 \times 1,000 = 62,055,000 \, \text{N/m}^2$

Now, calculate the load:

$\text{Load} = 62,055,000 \, \text{N/m}^2 \times 0.090 \, \text{m}^2$ $\text{Load} = 5,584,950 \, \text{N}$

Thus, the load the column can support is 5,584,950 N or 5,584.95 kN.

Would you like more details or have any questions?

Here are some related questions:

1. What is the significance of tensile stress in timber structures?
2. How do material properties affect the load-bearing capacity of timber?
3. What are common failure modes for timber columns under compression?
4. How would the load change if the cross-sectional area increased by 10%?
5. How can you determine the maximum stress a material can withstand before failure?

Tip: Always verify material properties, as factors like humidity and grain direction can affect timber strength.