Math Problem Statement

Using Pythagoras' theorem, calculate the length of PR. Give any decimal answers to 1 d.p.

P

50 cm

?

R

Q

48 cm

Solution

To calculate the length of PRPR using Pythagoras' Theorem, we need to understand the context of the triangle.

The Pythagorean theorem states: a2+b2=c2a^2 + b^2 = c^2 where:

  • aa and bb are the lengths of the two legs (the sides that meet at a right angle), and
  • cc is the length of the hypotenuse (the longest side of the right triangle).

In your case, the lengths given are:

  • PQ=50cmPQ = 50 \, \text{cm},
  • QR=48cmQR = 48 \, \text{cm}, and we are solving for PRPR, which is the hypotenuse.

Thus, applying the Pythagorean theorem: PQ2+QR2=PR2PQ^2 + QR^2 = PR^2 Substituting the known values: 502+482=PR250^2 + 48^2 = PR^2 2500+2304=PR22500 + 2304 = PR^2 4804=PR24804 = PR^2 Taking the square root of both sides: PR=4804PR = \sqrt{4804} PR69.3cmPR \approx 69.3 \, \text{cm}

So, the length of PRPR is approximately 69.3 cm (rounded to 1 decimal place).

Would you like further clarification or details on how this works?


Here are some follow-up questions for you:

  1. How do you apply Pythagoras' theorem in different types of triangles?
  2. What would happen if the triangle was not a right-angled triangle?
  3. How do you check if a triangle is a right-angled triangle?
  4. What is the relationship between the lengths of the sides in an isosceles right triangle?
  5. Can Pythagoras’ theorem be used in 3D geometry?

Tip: Remember, Pythagoras' theorem only works for right-angled triangles! Always verify if the triangle has a right angle before using it.

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagoras' Theorem
Right-Angle Triangles

Formulas

a^2 + b^2 = c^2 (Pythagorean Theorem)

Theorems

Pythagoras' Theorem

Suitable Grade Level

Grades 7-9