You have 150 grams of dry ice (solid CO₂), and it requires 85,650 Joules of energy to sublimate into gas at -78.5°C. What is the latent heat of sublimation for dry ice? (Hint: Use Q=mL​)

The latent heat of sublimation \( L \) for dry ice can be calculated using the formula:

\[
Q = mL
\]

where:
- \( Q \) is the heat energy required for sublimation (85,650 Joules),
- \( m \) is the mass of dry ice (150 grams),
- \( L \) is the latent heat of sublimation (what we need to find).

Rearranging the formula to solve for \( L \):

\[
L = \frac{Q}{m}
\]

First, convert the mass to kilograms since the latent heat is typically expressed in J/kg:

\[
m = 150 \, \text{g} = 0.150 \, \text{kg}
\]

Now substitute the values into the equation:

\[
L = \frac{85,650 \, \text{J}}{0.150 \, \text{kg}} = 571,000 \, \text{J/kg}
\]

Thus, the latent heat of sublimation for dry ice is \( 571,000 \, \text{J/kg} \).

Would you like more details or have any questions?

Here are 5 related questions to consider:
1. How does the latent heat of sublimation vary between different substances?
2. What is the physical significance of latent heat in phase changes?
3. How is the latent heat of vaporization different from sublimation?
4. How would you experimentally measure the sublimation of dry ice in a lab?
5. How much energy would be needed to sublimate 1 kg of dry ice?

**Tip:** Always ensure to convert units properly when working with physical quantities like mass, as using consistent units (kg, J) ensures accurate results.

You have 150 grams of dry ice (solid CO₂), and it requires 85,650 Joules of energy to sublimate into gas at -78.5°C. What is the latent heat of sublimation for dry ice? (Hint: Use Q=mL)

Discover how to calculate the latent heat of sublimation for dry ice (solid CO₂) using the formula Q = mL. In this example, 150 grams of dry ice requires 85,650 Joules of energy to sublimate into gas. Follow this guide to learn more about energy transfer and phase change in thermodynamics. Suitable for students in Grades 9-12.

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